Hit+the+Target!

=HiT THE TARGET! = =// Goal: //= To estimate and find the distance of a marble launched from a launcher at 55 degrees into a cylinder. = = =// Procedure: //=

1.) First, we found the distance of the marble by launching it straight up. We held a meter stick next to the launcher. We recorded five launching trials and took the average of the five distances. 2.) We knew the displacement, final velocity, and the acceleration so we used (Vf)^2=(Vi)^2+2a*d to find the initial velocity. 3.) Next, to find the distance between the cylinder and the tabletop, we measured the distance between the tabletop and the floor and subtracted it by the length of the cylinder. 4.) We needed to find the time, in order to find the distance from the moment the marble was launched to the highest point in the projectile. We knew the final velocity, initial velocity, and the acceleration so we used the equation Vf=Vi+at. 5.) Knowing the time, initial velocity, and final velocity, we were able to find the distance. We used the equation d=(Vi+Vf)/2*t 6.) After finding the distance for half the porabola, we multiplied it by two to get the whole porabola which is 1.004m. 7.) Next, we had to find the distance from the end of the porabola to the cylinder. (see picture 7 below) To do this, we subtracted 55 from 180, and got 125. Then we subtracted 90 from 125 to get 35 degrees. Then we did .732/tan(35) to get the x distance. We got 1.04m. 8.) Next, we add 1.04 to 1.004 to get 2.044m.

=// Data: //= = = =  = =// ﻿ //=
 * 1.) __Finding distance...__**
 * **Trial** || **Distance(cm)** ||
 * **1** || **73** ||
 * **2** || **77** ||
 * **3** || **72** ||
 * **4** || **73** ||
 * **5** || **80** ||
 * 73+77+72+73+80=375**
 * 375/5=75**
 * Average: 75 cm=.75m**


 * 2.)__Calculating initial velocity...__**
 * 2.)__Calculating initial velocity...__**


 * d=.75m**
 * Vi=?**
 * Vf=0**
 * a=-9.8**


 * (Vf)2=(Vi)2+2a*d**
 * 0=vi2+2*9.8*.75**
 * Vi=3.83m/s**


 * 3.)__Finding distance between tabletop and cylinder...__**
 * Height between Launcher and Floor= 1.07 m**
 * Height of cyclinder= .338m**
 * Height=.732**


 * 4.) __Calculating the time...__**
 * Vf=0**
 * Vi=3.137**
 * a=-9.8**
 * t=?**


 * Vf=Vi+at**
 * 0=3.137+-9.8t**
 * ..3201020408**
 * t=.32s**
 * 5.)__Calculating distance...__**
 * d=(Vi+Vf)/2*t**
 * (3.137+0)/2*0.3201**
 * d=0.502**

picture 7

180-55=125 degrees 125-90=35 degrees tan(35)=.732/dx =1.04m
 * 7.) The distance of the porabola is 1.004m**


 * 8.)**1.04+1.004=**2.044m**

2.044=distance from the launcher to the cylinder


 * percent error**
 * [(1.845-2.044)/2]*100**
 * = -10% error**

[[image:actual_distance_hit_the_target.JPG width="368" height="273"]]
=//** ﻿Reflection/Conclusion: **//= =The distance a marble traveled from a launcher launched at 55 degrees is 2.044m. At first, we had gotten a 17% error but later we noticed that we had done tan(55) instead of tan(35) so we ended up getting -10% error. We were not as accurate as we thought we were. We think we did okay.=